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Implement the following C++ code fragment in assembly language. Use the block structured .IF and .WHILE directives. Assume that all variables are 32-bit integers. int array[] = {3,1,4,1,5,9,2,6,5,3,5,8,9,7,9,3,2,3,8,4,6,2,6,4}; int lower = 2; int upper = 7; int ArraySize = sizeof array / sizeof lower; int index = 0; int sum = 0; while( index < ArraySize ) { if( array[index] >= lower && array[index] <= upper

User Aneesah
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Final answer:

A code snippet in C++ is converted to assembly language using block structured directives (.IF and .WHILE), with a while loop checking if each element in an integer array falls within a specified range (lower to upper bounds) and sums them if they do.

Step-by-step explanation:

The task is to implement a given C++ code fragment in assembly language using block structured directives (.IF and .WHILE). Given that the question is incomplete, we should complete the logical comparison in the if statement assuming it's comparing if the array element is within the lower and upper bound and then sum these values. Here is an outline of what the assembly code might look like, assuming the use of the MASM assembler:

.data
array DWORD 3,1,4,1,5,9,2,6,5,3,5,8,9,7,9,3,2,3,8,4,6,2,6,4 ; The array
lower DWORD 2
upper DWORD 7
ArraySize DWORD LENGTHOF array
sum DWORD 0
index DWORD 0

.code
main PROC
mov ecx, ArraySize ; Move ArraySize into counter (ecx)
mov esi, OFFSET array ; Move base address of array into source index (esi)

WHILE_loop:
.WHILE ecx > 0
mov eax, [esi]

.IF eax >= lower && eax <= upper
add sum, eax ; Add the value to sum if it's within bounds
.ENDIF

add esi, 4 ; Move to the next array element
dec ecx ; Decrease the loop counter
.ENDW

; Other operations

main ENDP

User Danique
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