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The temperature of a sample of liquid water is raised 30.0°C by the addition of 3680J of heat. What is the mass of the water?

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Final answer:

To find the mass of the water, we can use the equation Q = mcΔT, where Q is the heat added to the water, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. Using the given values, the mass of the water is 0.028g.

Step-by-step explanation:

To find the mass of the water, we can use the equation Q = mcΔT, where Q is the heat added to the water, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

First, we need to convert the heat added from joules to kilojoules. In this case, 3680J is equal to 3.68kJ.

Next, we can rearrange the equation to solve for the mass of the water:

m = Q / (cΔT)

Plugging in the values, we have:

m = 3.68kJ / (4.18J/(g°C) * 30.0°C) = 0.028g

Therefore, the mass of the water is 0.028g.

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