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Find the perimeter of the triangle whose vertices are (1,-4),(-5,0),and (-2,-9). Write exact answer do not round

Find the perimeter of the triangle whose vertices are (1,-4),(-5,0),and (-2,-9). Write-example-1
User Gingerbread
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1 Answer

23 votes
23 votes

We would calculate the distance between the vertices by applying the formula for calculating the distance between two points which is expressed as

distance = √(x2 - x1)^2 + (y2 - y1)^2

Considering (1,-4) and (-5,0),

x1 = 1, y1 = - 4

x2 = - 5, y2 = 0

Distance = √(- 5 - 1)^2 + (0 - - 4)^2 = √(- 6)^2 + (4)^2 = √52 = 2√13

Considering (-5,0),and (-2,-9),

x1 = - 5, y1 = 0

x2 = - 2, y2 = - 9

Distance = √(- 2 - - 5)^2 + (- 9 - 0)^2 = √(- 2 + 5)^2 + (- 9)^2 = √90 = 3√10

Considering (1,-4) and (-2,-9),

x1 = 1, y1 = - 4

x2 = - 2, y2 = - 9

Distance = √(- 2 - 1)^2 + (- 9 - - 4) = √(- 3)^2 + (- 5)^2 = √34

Perimeter = sum of the length of each side

Perimeter = 2√13 + 3√10 + √34

User Barzo
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