Question

Points A, B, and C are collinear, and B is between A and C. A is located at -5 and C is located at 10. If the length AB is 22, and BC is 32 - 10, what is the value of x?

Answer 1

The value of x is 0 as point B lies midway between points A and C.

Step-by-step explanation:

Given that points A, B, and C are collinear with B lying between A and C, and the coordinates of A and C are -5 and 10 respectively, we can find the length of BC by subtracting the x-coordinate of A from the x-coordinate of C. In this case, BC = 10 - (-5) = 15.

Now, we are given that the length of AB is 22 and the length of BC is 32 - 10 = 22. Therefore, AB = BC = 22.

Since AB = BC, we can conclude that point B lies midway between points A and C. Therefore, the value of x is 0.