Final answer:
The quadratic polynomial x² + 4x + 2 will have two real zeros, which can be found using the quadratic formula.
Step-by-step explanation:
The question asks about the number of zeros of the quadratic polynomial x² + 4x + 2. To find the zeros of this quadratic equation, we can use the quadratic formula, which is x = (-b ± √(b² - 4ac)) / (2a), where a, b, and c are the coefficients of the polynomial ax² + bx + c = 0. For our equation, a=1, b=4, and c=2. Plugging these into the formula we have x = (-4 ± √((4)² - 4(1)(2))) / (2(1)) = (-4 ± √(16 - 8)) / 2 = (-4 ± √(8)) / 2. Since we have a square root of a positive number (√(8)), this quadratic equation will have two real zeros.