Final answer:
The electric potential energy stored in the capacitor is 1.0 x 10^-8 joules, calculated using the formula PE = QV with the given charge of 1.0 x 10^-10 C and voltage of 100.0 V.
Step-by-step explanation:
To calculate the electric potential energy stored in a capacitor, we use the formula PE = QV, where PE stands for the potential energy, Q is the charge, and V is the voltage. Given the charge Q as 1.0 x 10^-10 C and the voltage V as 100.0 V, the calculation is straightforward. The potential energy, PE, of the capacitor is:
PE = QV = (1.0 x 10^-10 C) x (100.0 V) = 1.0 x 10^-8 J
Therefore, the capacitor stores 1.0 x 10^-8 joules of electrical potential energy.