Question

A 75 ml of HCI is titrated with 40 mL of 0.4 M NaOH solution. What is the molarity of the solution of NaOH solution

Answer 1

To determine the molarity of the NaOH solution, calculate the moles of HCl and then use the formula for molarity. Molarity of NaOH = 0.017775 mol / 0.04 L = 0.444375 mol/L

Step-by-step explanation:

To determine the molarity of the NaOH solution, we can use the equation:

Moles of NaOH = Moles of HCl

First, calculate the moles of HCl:

Moles of HCl = Volume of HCl x Molarity of HCl

Since 75 mL of HCl was used, the moles of HCl are:

Moles of HCl = 0.075 L x 0.237 mol/L = 0.017775 mol HCl

Since the molar ratio between NaOH and HCl is 1:1, the moles of NaOH are also 0.017775 mol. Now, use the formula for molarity:

Molarity of NaOH = Moles of NaOH / Volume of NaOH solution

Since 40 mL of NaOH was used, the volume of the NaOH solution is 0.04 L:

Molarity of NaOH = 0.017775 mol / 0.04 L = 0.444375 mol/L