Question

Marcy golf Phenom Kyle G. tees off from the 14th at Glen Abbey. The green (where the ball lands) is the same as the tee-off elevation. If Kyle hits the ball with a firing velocity of 38 m/s at an angle of 30° up from the horizontal. Find:

a) The time the ball is in the air.
b) The range (horizontal distance) the ball travels.
c) The maximum height the ball reaches above the tee-off elevation.

Answer 1

To determine the golf ball's trajectory when hit by Kyle G., the time in the air, range, and maximum height can be calculated using the initial velocity and launch angle with standard projectile motion equations.

Step-by-step explanation:

Calculating Projectile Motion for a Golf Ball

When Kyle G. tees off with a golf ball at Glen Abbey with a velocity of 38 m/s at a 30° angle above the horizontal, the following can be determined:

• a) Time in the air: The ball will undergo symmetric motion since it lands at the same elevation from which it was hit. Time of flight can be found using the formula t = (2 * v * sin(θ)) / g, where v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity (9.8 m/s²).
• b) Range of the ball: The horizontal distance can be determined by R = (v² * sin(2θ)) / g.
• c) Maximum height: This is given by H = (v² * sin²(θ)) / (2 * g).

By calculating these parameters, we can deduce the trajectory and overall displacement of the golf ball during its flight.