Question

The law of conservation of mass states; Nothing can be created or destroyed. Atoms are just rearranged. According to this, How many grams of CO2 would be produced in the reaction below? 27 g + 54 g g + 38g + 22g C,H,O2 + NaHCO, CO2 + NaC,H,O2 + H2O

Answer 1

In the given chemical reaction, the mass of CO2 produced can be determined by balancing the equation and using a proportion. The mass of CO2 is approximately 22 grams.

Step-by-step explanation:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. In the given reaction, we can see that the reactants include C,H,O2 (which represents a compound composed of carbon, hydrogen, and oxygen) and NaHCO, and the products include CO2, NaC,H,O2, and H2O. To determine the mass of CO2 produced, we need to balance the equation first.

The balanced equation for the given reaction is:

27 g + 54 g C,H,O2 + 38g NaHCO3 → CO2 + NaC,H,O2 + H2O

From the balanced equation, we can see that for every 54 grams of C,H,O2, 44 grams of CO2 are produced. Therefore, if we have 27 grams of C,H,O2, we can use a proportion to find the mass of CO2:

(27 g C,H,O2) / (54 g C,H,O2) = (x g CO2) / (44 g CO2)

Solving for x, the mass of CO2, we get:

x = (27 g C,H,O2 * 44 g CO2) / 54 g C,H,O2 ≈ 22 g CO2