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Which is the equation of a line that has a slope of -2/3 and passes through point (-3, -1)

y=-2/3x+1
y=-2/3x+ 3
y=-2/3x-1
y=-2/3x-3

User Fflorent
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1 Answer

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Final answer:

The equation of the line is y = -2/3x + 1.

Step-by-step explanation:

The equation of a line that has a slope of -2/3 and passes through point (-3, -1) can be found using the point-slope form of a linear equation.

The point-slope form is given by the equation y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.

Plugging in the values (-3, -1) and m = -2/3, we get:

y - (-1) = -2/3(x - (-3))

Simplifying the equation gives:

y + 1 = -2/3(x + 3)

Further simplifying and converting to slope-intercept form gives:

y = -2/3x + 1

User Marena
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