Question

A sample of SO2 gas has a volume of 18.0 L at a temperature of 35.0°C. At what temperature, in °C, will the gas have a volume of 13.0 L? (Hint: Convert ° C to K)

Answer 1

-50.6 °C

Step-by-step explanation

Given:

Initial volume, V₁ = 18.0 L

Initial teperature, T₁ = 35.0°C = (35. + 273.15 K) = 308.15 K

Final volume, V₂ = 13.0 L

What to find:

The finaltemperatrure, T₂ in °C

Step-by-step solution:

The final temperature, T₂ can be calculated using Charle's lawfequation.

`\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ \\ \Rightarrow T_2=(T_1V_2)/(V_1) \end{gathered}`

Plugging the values of the given parameters into the formula, we have;

`T_2=\frac{308.15\text{ }K*13.0\text{ }L}{18.0\text{ }L}=222.55\text{ }K`

The final temperature, T₂ in °C = (222.55 - 273.15 ) = -50.6 °C