Question

A 2 kg ball starts from the ball release and rolls along the track. What is the height of the track at Point W if the velocity of the ball is 6.3 m/s?

Answer 1

The height of the track at Point W can be calculated using the principle of conservation of energy. Using the equation mgh = (1/2)mv^2, we can rearrange it to solve for h. Substituting the given values, we find that the height is 2.57 meters.

Step-by-step explanation:

The height of the track at Point W can be determined using the principle of conservation of energy. We can use the equation:

mgh = (1/2)mv^2

Where m is the mass of the ball, g is the acceleration due to gravity, h is the height of the track at Point W, and v is the velocity of the ball. Rearranging the equation to solve for h, we get:

h = (1/2) v^2 / g

Substituting the given values, we have:

h = (1/2)(6.3 m/s)^2 / 9.8 m/s^2

Calculating this gives:

h = 2.57 meters