Question

A frog leap hoizontally from a rock 15m high with a speed of 5.5 m/s . How point far from the base of the rock will the frog land?

Answer 1

The frog will land approximately 9.735 meters away from the base of the rock.

Step-by-step explanation:

The horizontal distance the frog will travel can be calculated using the formula:

Horizontal Distance = Initial Velocity * Time

In this case, the initial velocity of the frog is 5.5 m/s and the time can be calculated using the formula:

Time = sqrt(2 * Height / g)

where Height is the height of the rock and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the values, we have:

Time = sqrt(2 * 15 / 9.8) ≈ 1.77 seconds

Now, substituting the values of initial velocity and time in the horizontal distance formula:

Horizontal Distance = 5.5 * 1.77 ≈ 9.735 meters

Therefore, the frog will land approximately 9.735 meters away from the base of the rock.