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What is the Y-component of a vector A, which is of magnitude 16 and at 45° angle to the horizontal?

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Final answer:

The Y-component of a vector with magnitude 16 and at a 45° angle to the horizontal is calculated as Ay = 16 * sin(45°), which equals approximately 11.3.

Step-by-step explanation:

To calculate the Y-component of a vector A, you can use trigonometry, specifically sine and cosine functions. The Y-component Ay of a vector is calculated using the sine function, which in mathematical terms is Ay = A * sin(θ), where A is the magnitude of the vector and θ is the angle it makes with the horizontal axis.

In your case, the magnitude A is given as 16 and the angle θ is 45°. By substituting these values into the formula, we get Ay = 16 * sin(45°). Since sin(45°) is \(√2/2\), Ay then becomes 16 * (\(√2/2\)) which equals to 11.3, when rounded to one decimal place.

User Abhijith Prabhakar
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