Question

A diver jumps off a diving board. The diver's height above the water, in meters, is represented by the function , where t is the number of seconds since the diver jumped. How high above the water is the diver after 2 seconds? How high above the water is the diver after 3 seconds?

Answer 1

To find the height above the water, you can use the equation h(t) = -4.9t^2 + initial height. After 2 seconds, the diver is 17.80 meters below the initial height. After 3 seconds, the diver is 42.30 meters below the initial height.

Step-by-step explanation:

To find the height above the water, we can use the equation h(t) = -4.9t^2 + initial height, where t is the time in seconds since the diver jumped.

For the given problem, the diver starts at a height of 1.80 meters above the water. To find the height after 2 seconds, substitute t = 2 into the equation: h(2) = -4.9(2)^2 + 1.80 = -19.6 + 1.80 = -17.80 meters.

Similarly, to find the height after 3 seconds, substitute t = 3 into the equation: h(3) = -4.9(3)^2 + 1.80 = -44.1 + 1.80 = -42.30 meters.