Question

On Tuesday, Wallace drove 3 miles farther than half as far as he drove on Monday. Altogether, Wallace drove 33 miles. Write an equation that represents this scenario and determine how far Wallace drove on Tuesday.

Answer 1

By setting up an equation based on the scenario described, we deduce that Wallace drove 20 miles on Monday and 13 miles on Tuesday.

Step-by-step explanation:

Let's denote the distance Wallace drove on Monday as x miles. According to the scenario, on Tuesday, Wallace drove 3 miles farther than half as far as he drove on Monday. This can be expressed as (1/2)x + 3 miles. The total distance driven over the two days is 33 miles, which creates the equation: x + (1/2)x + 3 = 33.

First, we combine like terms by adding x and (1/2)x:

(1 + 1/2)x = (3/2)x

Then, we substitute this back into the equation:

(3/2)x + 3 = 33

Next, we subtract 3 from both sides to isolate the term with x:

(3/2)x = 30

Finally, we divide both sides by (3/2) to solve for x:

x = 30 / (3/2) = 30 * (2/3) = 20

So, Wallace drove 20 miles on Monday. Using this information, we can find out how far he drove on Tuesday:

(1/2) * 20 + 3 = 10 + 3 = 13 miles on Tuesday.