Question

Fireworks are shot upward at a speed of

24.5 ft/sec from a roof of a skyscraper 185
feet tall. How high will the fireworks be
after 2.5 seconds?

Answer 1

The fireworks will be approximately 346.25 feet high after 2.5 seconds.

Step-by-step explanation:

To determine how high the fireworks will be after 2.5 seconds, we can use the equation of motion for vertical motion: h = h0 + v0t + (1/2)gt2.

Given that the initial vertical position (h0) is 185 feet, the initial vertical velocity (v0) is 24.5 ft/sec, and the time (t) is 2.5 seconds, we can substitute these values into the equation.

h = 185 + 24.5(2.5) + (1/2)(32)(2.5)2 = 185 + 61.25 + (1/2)(32)(6.25) = 185 + 61.25 + 100 = 346.25 feet.

Therefore, the fireworks will be approximately 346.25 feet high after 2.5 seconds.