Final answer:
To find the measure of ∠JBC, we use the property that the sum of angles in a triangle is 180 degrees. Since ∠ABC is congruent to ∠DBJ, and given m∠ABJ = 28°, we establish that both ∠ABC and ∠DBJ measure 76°. Consequently, ∠JBC also measures 76°.
Step-by-step explanation:
To find the measure of the ∠JBC given that m∠ABJ = 28° and ∠ABC ≅ ∠DBJ, we use the concept that the sum of angles in a triangle is 180 degrees. Since ∠ABC and ∠DBJ are congruent, they have the same measure. First, let's find the measure of ∠ABC and subsequently the measure of ∠JBC within △JBC.
We already have one angle of the triangle, which is ∠ABJ = 28°. If we denote the measure of ∠ABC (which is the same as the measure of ∠DBJ) as x, and we denote the measure of ∠JBC as y, our equation based on the triangle angle sum property is:
28° + x + x = 180°
This simplifies to:
28° + 2x = 180°
Subtracting 28° from both sides gives:
2x = 152°
Dividing by 2, we find:
x = 76°
So, both ∠ABC and ∠DBJ measure 76°. Next, we use this information to find y:
28° + 76° + y = 180°
Add 28° and 76° to get 104°:
104° + y = 180°
Finally, subtract 104° from both sides to get:
y = 76°
Therefore, the measure of ∠JBC is also 76° in triangle JBC.