Final answer:
To find the zeros of f(x) = x²+2x-3 using the quadratic formula, substitute the coefficient values into the formula and solve for x.
Step-by-step explanation:
To find the zeros of the function f(x) = x²+2x-3 using the quadratic formula, we can plug the coefficients of the quadratic equation into the formula:
x = (-b ± √(b²-4ac)) / (2a)
- a = 1, b = 2, and c = -3
- Substituting these values into the quadratic formula, we get:
- x = (-2 ± √(2²-4(1)(-3))) / (2(1))
- Simplifying further:
- x = (-2 ± √(4+12)) / 2
- x = (-2 ± √16) / 2
- x = (-2 ± 4) / 2
- Therefore, the zeros of the function f(x) = x²+2x-3 are x = -3 and x = 1.