44.9k views
1 vote
One rectangle has the length of the width of 2x.Another rectangle has a length of x-2cm and a width of 32 cm find the value of x so that the rectangles have the same area.

User Roych
by
8.3k points

1 Answer

4 votes

Final answer:

To ensure both rectangles have the same area, we set their areas equal to each other and solve for x, which in this case yields x = 4 as the solution.

Step-by-step explanation:

To find the value of x so that two rectangles have the same area, we need to set the areas of both rectangles equal to each other. The area of a rectangle is found by multiplying its length by its width.

For the first rectangle with dimensions 2x by 2x, the area is (2x) × (2x), which simplifies to 4x². For the second rectangle with dimensions (x-2) cm by 32 cm, the area is (x-2) × 32 which simplifies to 32x - 64 cm².

Setting these two areas equal, we get:

4x² = 32x - 64

Now, we will solve this quadratic equation for x.

4x² - 32x + 64 = 0

Dividing the entire equation by 4 reduces it to:

x² - 8x + 16 = 0

Factoring the quadratic equation, we find:

(x - 4)(x - 4) = 0

So, x = 4 is the solution. This means that when x is 4, both rectangles will have the same area.

User Sean McCauliff
by
9.1k points