44.9k views
1 vote
One rectangle has the length of the width of 2x.Another rectangle has a length of x-2cm and a width of 32 cm find the value of x so that the rectangles have the same area.

User Roych
by
8.3k points

1 Answer

4 votes

Final answer:

To ensure both rectangles have the same area, we set their areas equal to each other and solve for x, which in this case yields x = 4 as the solution.

Step-by-step explanation:

To find the value of x so that two rectangles have the same area, we need to set the areas of both rectangles equal to each other. The area of a rectangle is found by multiplying its length by its width.

For the first rectangle with dimensions 2x by 2x, the area is (2x) × (2x), which simplifies to 4x². For the second rectangle with dimensions (x-2) cm by 32 cm, the area is (x-2) × 32 which simplifies to 32x - 64 cm².

Setting these two areas equal, we get:

4x² = 32x - 64

Now, we will solve this quadratic equation for x.

4x² - 32x + 64 = 0

Dividing the entire equation by 4 reduces it to:

x² - 8x + 16 = 0

Factoring the quadratic equation, we find:

(x - 4)(x - 4) = 0

So, x = 4 is the solution. This means that when x is 4, both rectangles will have the same area.

User Sean McCauliff
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.