Question

plot the point , (b) find the distance between the point (c) find the midpoint of the line segment joining the point (-3,2) , (3, -2)​

Answer 1

The distance between the points are 9.85 units and the midpoint is (0, 0)

Finding the distance and the midpoint between the points

From the question, we have the following parameters that can be used in our computation:

The points

Where, we have

(-3, 2) and (3, -2)

The distance between the points can be calculated using

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

Using the above as a guide, we have the following:

d = √[(-3 - 3)² + (2 + 2)²]

Evaluate the squares in the expression

So, we have

d = √[81 + 16]

This gives

d = √97

So, we have

d = 9.85

Hence, the distance is 9.85 units

Also, we have the midpoint to be

Midpoint = 1/2(x₂ + x₁, y₂ + y₁)

So, we have

Midpoint = 1/2(-3 + 3, 2 - 2)

Evaluate

Midpoint = (0, 0)

So, the midpoint is (0, 0)