Final answer:
The slope of 10x+8y=73 is -5/4. The lines 10x+8y=73 and 4x+5y=2 are perpendicular.
Step-by-step explanation:
To find the slope of the equation 10x+8y=73, we first need to rearrange it in the form y = mx + b, where m represents the slope. Subtracting 10x from both sides of the equation gives us 8y = -10x + 73. Dividing both sides by 8, we get y = (-10/8)x + (73/8). Therefore, the slope of the equation is -10/8 or -5/4.
To determine whether the lines 10x+8y=73 and 4x+5y=2 are perpendicular, we can compare their slopes. The slope of 4x+5y=2 is -4/5. Perpendicular lines have slopes that are negative reciprocals of each other. The slope of the first equation, -5/4, is the negative reciprocal of -4/5. Therefore, the lines are perpendicular.