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What is the area of a rectangle if the length is 4 and the width is (2ab - 3b)?

User Jrdi
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Final answer:

The area of the rectangle is 8ab² - 12b² square units.the final expression representing the area. The resulting expression, 8ab² - 12b², represents the area of the rectangle in terms of the provided variables.

Step-by-step explanation:

To find the area of a rectangle, you multiply its length by its width. In this case, the length is given as 4 units, and the width is (2ab - 3b) units. To determine the area, multiply the length (4) by the width [(2ab - 3b)]. This results in the expression for the area: 4 * (2ab - 3b) = 8ab² - 12b² square units. The area of the rectangle is therefore expressed as 8ab² - 12b² square units.

This calculation utilizes the formula for the area of a rectangle, where the product of its length and width gives the total space enclosed by the rectangle. In this case, substituting the given values for length and width into the formula yields the final expression representing the area. The resulting expression, 8ab² - 12b², represents the area of the rectangle in terms of the provided variables.

User Zvonicek
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