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How much time does it take for a car to come to rest if it has an initial

speed of 22 m/s and slows with an acceleration of -6.1 m/s^2? *

1 Answer

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Final answer:

Using the formula for uniform acceleration, the time it takes for a car to come to rest from an initial speed of 22 m/s with an acceleration of -6.1 m/s^2 is approximately 3.61 seconds.

Step-by-step explanation:

To calculate how much time it takes for a car with an initial speed of 22 m/s to come to rest with an acceleration of -6.1 m/s2, we can use the formula v = u + at where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the car is coming to rest, the final velocity v will be 0 m/s. Rearranging the formula to solve for t, we get t = (v - u) / a. Plugging in the values gives t = (0 - 22) / (-6.1).

By calculating this expression, we find that the time taken t is approximately 3.61 seconds for the car to come to rest. It is important to note that the negative sign in acceleration indicates deceleration, which is why we are able to use this sign convention in our calculation.

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