Question

Amy is two years older than Tiana. Samiyah is twice as old as Samiyah. The sum of their ages is 46. How old are each of the three girls?​

Answer 1

Due to a presumed typo regarding Samiyah's age, a placeholder has been used to solve the problem, resulting in Tiana being 11 years old, Amy being 13 years old, and Samiyah being 22 years old, assuming Samiyah is twice the age of Tiana.

Step-by-step explanation:

There seems to be a typo in your question, since it is stated that 'Samiyah is twice as old as Samiyah,' which doesn't provide any useful information. Assuming that there's another girl whose age we can use to compare Samiyah's age, let's denote that person as X. Let's define their ages as follows: Amy = Tiana + 2, Samiyah = 2 * X, and Tiana = X.

So the equation based on the information given about their ages would be: (Tiana + 2) + (2 * Tiana) + Tiana = 46.

Combining like terms gives us 4 * Tiana + 2 = 46. Subtracting 2 from both sides, we get 4 * Tiana = 44. Dividing both sides by 4 gives us Tiana = 11.

Now, we can find Amy and Samiyah's ages:

• Amy = Tiana + 2 = 11 + 2 = 13
• Samiyah = 2 * Tiana = 2 * 11 = 22

So, Tiana is 11 years old, Amy is 13 years old, and Samiyah is 22 years old.