Final answer:
To find out how many grams of benzoic acid are needed to react with 20.00 mL of NaOH solution, calculate the number of moles of NaOH, use the 1:1 reaction ratio to find moles of benzoic acid, and then convert these moles to grams using the molar mass of benzoic acid.
Step-by-step explanation:
To calculate how many grams of benzoic acid are necessary to react with 20.00 mL of NaOH solution, first, the concentration of NaOH should be known. Assuming we have a 0.1 M NaOH solution (since this information was not provided), we use the following steps:
- Determine the number of moles of NaOH in 20.00 mL (or 0.02000 L) of solution using the formula: moles = volume (L) × molarity (M).
- Since the reaction between benzoic acid and NaOH is a 1:1 mole ratio, the number of moles of benzoic acid needed will equal the number of moles of NaOH.
- Convert the moles of benzoic acid to grams using its molar mass (122.12 g/mol) with the formula: grams = moles × molar mass (g/mol).
Step 1: Calculate the number of moles of NaOH:
# moles of NaOH = volume (L) × molarity (M) = 0.02000 L × 0.1 M = 0.002 mol NaOH
Step 2: Calculate the mass of benzoic acid needed:
# moles of benzoic acid = 0.002 mol (since the reaction ratio is 1:1)
Step 3: Convert moles of benzoic acid to grams:
mass of benzoic acid = # moles × molar mass = 0.002 mol × 122.12 g/mol = 0.24424 g
Hence, 0.24424 grams of benzoic acid is necessary to react with 20.00 mL of 0.1 M NaOH solution.