Question

Jamaica’s population of 2,466,000 in 1990 was expected to grow exponentially by 1.1% each year. If you were to write an exponential equation representing the situation, what would the growth factor be?

Answer 1

The growth factor for Jamaica's population growth, with an annual increase of 1.1%, would be 1.011, leading to the exponential equation P(t) = 2,466,000 × 1.011t.

Step-by-step explanation:

The exponential equation representing Jamaica's population growth based on the information provided would have a growth factor of 1.011. This factor is derived from the given annual growth rate of 1.1%. Therefore, the exponential growth equation can be written as P(t) = P0 × (1 + r)t, where P0 represents the initial population size, r represents the growth rate as a decimal (1.1% or 0.011), and t represents time in years. For Jamaica's case in 1990, this would be P(t) = 2,466,000 × 1.011t.