Final answer:
To bring 2.5 kg of water from 0°C to 16°C, we need 167.36 J of thermal energy.
Step-by-step explanation:
To calculate the amount of thermal energy needed, we can use the equation:
Q = mcΔT
Where Q is the thermal energy, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
Given that the mass of water is 2.5 kg, the specific heat capacity of water is 4.184 J/g °C, and the change in temperature is 16°C, we can substitute these values into the equation:
Q = (2.5 kg) * (4.184 J/g °C) * (16°C)
Calculating this, we get:
Q = 167.36 J
Therefore, the amount of thermal energy needed to bring 2.5 kg of water from 0°C to 16°C is 167.36 J.