Final answer:
The energy required to convert 20.5 g of water at 25.0 °C to steam at the same temperature is 46330 Joules, calculated using the latent heat of vaporization.
Step-by-step explanation:
To calculate the energy needed to turn 20.5 g of water at 25.0 °C to steam at the same temperature, we need to consider the heat needed to raise the temperature to the boiling point and the heat of vaporization. The specific heat capacity of water is 4.184 J/g°C, but since the water is already at 25.0 °C, we only need to calculate the energy based on the latent heat of vaporization, which is approximately 2260 J/g. Hence, the energy needed is:
Energy = mass × latent heat of vaporization
Energy = 20.5 g × 2260 J/g
Energy = 46330 Joules
Therefore, 46330 Joules of energy are required to convert 20.5 g of water at 25.0 °C to steam at 25.0 °C.