Question

Identify the quadratic function that is in standard form has zeros 4 and −7.

f(x) = x2 + 3x + 28
f(x) = x2 − 11x + 28
f(x) = x2 + 11x − 28
f(x) = x2 + 3x − 28

Answer 1

The quadratic function in standard form with zeros at 4 and -7 is f(x) = x^2 + 3x - 28.

Step-by-step explanation:

The quadratic function in standard form with zeros at 4 and -7 is f(x) = (x - 4)(x + 7).

We can expand this expression to get:
f(x) = x^2 + 7x - 4x - 28
f(x) = x^2 + 3x - 28

Therefore, the correct quadratic function in standard form is f(x) = x^2 + 3x - 28.