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One airplane is located 200 km north and 50 km east of an airport. A secound plane at the same altitude is located 30 km north and 100 km west

the distance between the planes is closest to:
A. 150 km
B. 200 km
C. 300km
D. 350km
E. 400km

1 Answer

2 votes

Final answer:

The distance between the planes is closest to 225 km.

Step-by-step explanation:

To find the distance between the two planes, we can use the Pythagorean theorem. First, we find the horizontal distance between the two planes:

50 km + 100 km = 150 km.

Then, we find the vertical distance between the two planes: 200 km - 30 km = 170 km.

Finally, we can use the Pythagorean theorem to find the diagonal distance:

sqrt((150 km)^2 + (170 km)^2) ≈ 226.72 km.

Therefore, the distance between the planes is closest to 225 km (option A).

User Kravemir
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