Question

Indicate the concentration of each ion or molecule present in the following solution.

A mixture of 45.0 mL of 0.272 M NaCl and 65.0 mL of 0.0247 M (NH4)2CO3 . Assume that the volumes are additive.

Express your answer numerically using three significant figures. If there is more than one answer, separate them by a comma.

Answer 1

To find the concentration of each ion in the given solution, use the concept of molarity and the volumes of the solutions. Multiply the molarity by the volume to find the concentration of each ion or molecule.

Step-by-step explanation:

To find the concentration of each ion or molecule present in a solution, you can use the concept of molarity and the volumes of the respective solutions. In this case, we have a mixture of 45.0 mL of 0.272 M NaCl and 65.0 mL of 0.0247 M (NH4)2CO3.

To calculate the concentration of each ion, we can use the fact that the volumes are additive.

The concentration of Na+ ions in the NaCl solution can be found by multiplying the molarity by the volume: 0.272 M x 45.0 mL = 12.24 mmol.

The concentration of CI- ions in the NaCl solution is the same since it is a 1:1 electrolyte.

In the (NH4)2CO3 solution, the concentration of NH4+ ions can be found by multiplying the molarity by the volume: 0.0247 M x 65.0 mL = 1.60 mmol.

The concentration of CO32- ions in the (NH4)2CO3 solution is also found the same way: 0.0247 M x 65.0 mL = 1.60 mmol.