Question

A rocket, initially at rest, steadily gains speed at a rate of 16.0m/s² for 3.30s during take-off. What was the rocket's top speed?

Answer 1

The rocket's top speed after accelerating steadily at 16.0 m/s² for 3.30 seconds would be 52.8 m/s.

Step-by-step explanation:

To find the rocket's top speed, we can use the formula that relates final velocity (v), initial velocity (v0), acceleration (a), and time (t) which is v = v0 + at. Since the rocket is initially at rest, the initial velocity v0 is 0 m/s. Knowing the acceleration of the rocket is 16.0 m/s² and it accelerates for a duration of 3.30 s, we can calculate the top speed by plugging these values into the equation:

v = 0 m/s + (16.0 m/s² * 3.30 s) = 52.8 m/s

Therefore, the rocket's top speed after accelerating for 3.30 seconds is 52.8 m/s.