Question

Two airplanes leave an airport at the same time. The velocity of the first airplane is 660 m/h, at a heading of 61.3. The velocity of the second is 640 m/h at a heading of 180°. How far apart are they after 2.2 h?

Answer 1

To calculate how far apart the two airplanes are after 2.2 hours, we first determine how far each has traveled based on their given velocities and then use vector addition or the Pythagorean theorem to find the separation distance between the two planes.

Step-by-step explanation:

To determine how far apart the two airplanes are after 2.2 hours, we need to calculate the distance each has traveled and then determine their positions relative to the starting point. The first airplane is flying at a velocity of 660 m/h at a heading of 61.3°, while the second airplane is flying at a velocity of 640 m/h at a heading of 180° (due south).

To find the distance each airplane has traveled, we multiply their velocities by the time:

• Distance of first airplane = 660 m/h * 2.2 h = 1452 m
• Distance of second airplane = 640 m/h * 2.2 h = 1408 m

Now, we need to calculate how far apart they are using vector addition or by applying the Pythagorean theorem and trigonometric functions since they are moving along different headings. After doing the calculations, we would find the separation distance between the two planes.