Final answer:
To convert 1 - (sqrt3)i to polar form, we can use the magnitude and angle formulas. The magnitude is found using the formula r = sqrt(x^2 + y^2), and the angle is found using the formula theta = arctan(y/x).
Step-by-step explanation:
To convert 1 - (sqrt3)i to polar form, we need to find its magnitude (absolute value) and angle. The magnitude can be found using the formula r = sqrt(x^2 + y^2), where x is the real part and y is the imaginary part. In this case, x = 1 and y = -sqrt(3), so the magnitude is r = sqrt(1^2 + (-sqrt(3))^2) = sqrt(4) = 2. The angle can be found using the formula theta = arctan(y/x). In this case, theta = arctan((-sqrt(3))/1) = -pi/3.
Therefore, the complex number 1 - (sqrt3)i can be represented in polar form as 2(cos(-pi/3) + isin(-pi/3)).