Final answer:
The respective accelerations of a ball with a mass of 0.25 kg when hit with forces of 50 N and 100 N would be 200 m/s^2 and 400 m/s^2, calculated using Newton's second law of motion.
Step-by-step explanation:
The question deals with calculating the acceleration of a ball when different forces are applied to it. According to Newton's second law of motion, the acceleration (a) of an object is directly proportional to the net force (F) acting upon it and inversely proportional to its mass (m), as described by the formula a = F/m.
When a force of 50 N is applied to a ball of mass 0.25 kg, the acceleration can be calculated as follows:
- a1 = F1 / m = 50 N / 0.25 kg = 200 m/s2
Similarly, when a force of 100 N is applied:
- a2 = F2 / m = 100 N / 0.25 kg = 400 m/s2
Therefore, the respective accelerations would be 200 m/s2 and 400 m/s2 when hit with forces of 50 N and 100 N, respectively.