Question

A sphere has radius 50mm and mass 1kg falling vertically through air of density 1.2kg/my attains a steady velocity of 11m/ the above equation is applied to it's fall what is the value of k?​

Answer 1

To find the value of k, we need to use the equation m_r = k and substitute the given values for the radius and mass of the sphere. Simplifying the equation, we find that k = 20 kg/m.

Step-by-step explanation:

To find the value of k, we need to use the equation provided and solve for k. The equation given is:

mr = k

Given that the radius of the sphere is 50mm and the mass is 1kg, we can substitute these values into the equation:

(1kg) = k(50mm)

Converting mm to meters (1m = 1000mm), we get:

(1kg) = k(0.05m)

Simplifying the equation, we find that:

k = 1kg / 0.05m = 20 kg/m