Question

Design Sabrina has designed a rectangular painting that measures 50 feet in length

and 40 feet in width. Alfred has also designed a rectangular painting, but it measures
x feet shorter on each side. When x = 3, what is the area of Alfred's painting?

Answer 1

The area of Alfred's painting when x = 3 is 1,739 square feet, calculated by subtracting 3 from both the length and width of Sabrina's painting and then multiplying the resulting dimensions.

Step-by-step explanation:

When x = 3, the dimensions of Alfred's painting would be 50 - 3 = 47 feet in length, and 40 - 3 = 37 feet in width because it is x feet shorter on each side than Sabrina's painting. To find the area of Alfred's painting, you need to multiply the length by the width:

Area = length × width

Area = 47 feet × 37 feet

Area = 1,739 square feet

Therefore, the area of Alfred's painting when x = 3 is 1,739 square feet.