Question

A force of 30 N is exerted on an object on a frictionless surface for a distance of 6.0 meters. If the object has a mass of 10 kg, calculate its velocity. Use significant figures.g = 9.8 m/s^2v=○ 36 m/s○ 18 m/s○ 6.0 m/s○ 4.0 m/s

Answer 1

Given,

The force exerted, F=30 N

The distance for which the force is applied, s=6.0 m

The mass of the object, m=10 kg

The initial velocity, u=0 m/s

From Newton's second law,

`F=ma`

Thus the acceleration of the body is given by,

`a=(F)/(m)`

From the equation of the motion,

`\begin{gathered} v^2=u^2+2as \\ \Rightarrow v^2=u^2+2*(F)/(m)* s \\ \Rightarrow v=\sqrt[]{u^2+2*(F)/(m)* s} \end{gathered}`

On substituting the known values, the final velocity of the object is

`\begin{gathered} v=\sqrt[]{0+2*(30)/(10)*6} \\ =6\text{ m/s} \end{gathered}`

Thus the velocity of the object is 6 m/s