Final answer:
The equation of a line with a slope of 3 and a y-intercept of -9 is y = 3x - 9. The equation of a line with a slope of -4 through the point (5, -1) is y = -4x + 19.
Step-by-step explanation:
The equation of a line with a slope of 3 and a y-intercept of -9 can be written in the slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept. Therefore, the equation is y = 3x - 9.
To write the equation of a line with a slope of -4 through the point (5, -1), we can use the point-slope form: y - y1 = m(x - x1). Plugging in the given values, the equation becomes y - (-1) = -4(x - 5). Simplifying, we get y + 1 = -4x + 20. Rearranging the equation, we have y = -4x + 19.