Final answer:
The function f(x) = 2 - 3 is a constant function and equal to -1. Its derivative f'(x) is 0, and hence has no x-intercept as it represents a horizontal line along y=0 on the graph.
Step-by-step explanation:
The provided function f(x) = 2 - 3 is a constant function and does not depend on x, effectively making it f(x) = -1. As such, this function has no x-intercept because it is a horizontal line below the x-axis, and it never crosses the x-axis. When considering the derivative of a constant function, f'(x), it is equal to zero since the slope of a constant function is zero. Hence, finding the x-intercept of f'(x) is not applicable because the derivative of a constant function does not graph as a line that could intersect the x-axis; it's simply a horizontal line along the y=0 axis.