Final Answer:
11/12 fraction of the donuts had sprinkles, in this situation.
Step-by-step explanation:
1. Determine the total number of donuts:
Since there are 12 donuts in a dozen and Isaiah brought two dozen, we multiply 12 by 2:
2 dozen × 12 donuts/dozen = 24 donuts
2. Find the number of vanilla frosted donuts with sprinkles:
Isaiah brought donuts, where half of them had vanilla frosting with sprinkles. So we divide the total number by 2:
24/2 = 12 vanilla frosted donuts with sprinkles
3. Account for the strawberry frosted donuts: There are 2 donuts with strawberry frosting and cream filling.
4. Determine the number of chocolate frosted donuts with sprinkles:
To find the remaining number of donuts, we subtract the number of vanilla frosted donuts with sprinkles and strawberry frosted donuts from the total number of donuts:
24 - 12 - 2 = 10 chocolate frosted donuts with sprinkles
5. Calculate the total number of donuts with sprinkles:
We add the vanilla frosted donuts with sprinkles to the chocolate frosted donuts with sprinkles to get the total number with sprinkles:
12 vanilla + 10 chocolate = 22 donuts with sprinkles
6. Find the fraction of donuts with sprinkles:
To find the fraction, we divide the number of donuts with sprinkles by the total number of donuts: 22/24
7. Simplify the fraction if possible:
We can simplify this fraction by dividing the numerator and denominator by their greatest common divisor (GCD), which for 22 and 24 is 2: 22/24 = 11/12
Therefore, the fraction of the donuts that have sprinkles is 11/12.
Complete question:
Isaiah brought two dozen donuts to a class party. Half of the donuts had vanilla frosting with sprinkles, 2 had strawberry frosting with cream filling, and the rest had chocolate frosting with sprinkles. What fraction of the donuts had sprinkles? There are 12 donuts in a dozen.