Question

From the data in the following questions calculate the missing quantity.

-a) V. = 22.4L; T, = 0°C; T, = 91°C; V2 = ?L
b) V. = 125 mL; T, = ?; T2 = 25°C; V2 = 100 mL
c) V, = ? L; T, = 400 K; T, = 175 K; V. = 6.20 L
d) V = 250 mL; T = 298 K; T2 = ? K; V, = 273 mL

Answer 1

The question involves using Charles's Law to find the new volume of a gas when it is heated from one temperature to another. By using the formula V1 / T1 = V2 / T2 and substituting the given values, the final volume V2 can be calculated.

Step-by-step explanation:

The student's question is related to the application of Charles's Law, which states that the volume of a fixed mass of gas at constant pressure is directly proportional to its temperature in kelvins. For the provided example, we are given an initial volume (V1) of 2.20 L at an initial temperature (T1) of 22°C, which is equivalent to 295 K. The gas is then heated to a final temperature (T2) of 71°C, or 344 K, and we must calculate the final volume (V2).

To find V2, we can use the formula derived from Charles's Law:

V1 / T1 = V2 / T2, rearranging to solve for V2 gives us V2 = (V1 x T2) / T1.

Substituting the given values into this equation gives us V2 = (2.20 L x 344 K) / 295 K, which after calculating gives us the new volume of the gas at 71°C.