Question

The combustion reaction of methane is represented by the following equation: CH₄(g) + 2O₂(g) → 2H₂O(g) + CO₂(g). Calculate the volume of carbon dioxide gas produced when 50 liters of methane are burned in the reaction.

Answer 1

To calculate the volume of carbon dioxide gas produced when 50 liters of methane are burned, convert the volume of methane to moles and then use the stoichiometric ratio to find the volume of carbon dioxide.

Step-by-step explanation:

The combustion reaction of methane is represented by the equation:

CH4(g) + 2O2(g) → 2H2O(g) + CO2(g)

To calculate the volume of carbon dioxide gas produced when 50 liters of methane are burned, we need to determine the stoichiometry of the reaction.

The balanced equation tells us that for every 1 mole of methane burned, 1 mole of carbon dioxide is produced. Therefore, we need to convert the volume of methane to moles and then use the stoichiometric ratio to find the volume of carbon dioxide.

1 mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. So, 50 liters of methane is equal to 50/22.4 = 2.23 moles of methane. Since the stoichiometric ratio is 1 mole of methane to 1 mole of carbon dioxide, the volume of carbon dioxide gas produced will also be 2.23 liters.