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Find x. 2eˣ² - (ᵉ²+2)x+e=0​

User SexyMF
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Final answer:

To solve the equation 2eˣ² - (ᵉ²+2)x+e=0, rearrange it into a quadratic equation and use the quadratic formula to find the values of x.

Step-by-step explanation:

To solve the equation 2eˣ² - (ᵉ²+2)x+e=0, we can rearrange it into a quadratic equation ax² + bx + c = 0. The equation becomes x² + (0.0211x) - 0.0211 = 0. We can then use the quadratic formula to find the values of x which are approximately x = -0.0024 and x = 0.00139. However, since x = -0.0024 is negative, which is not possible in real life, we conclude that x = 0.00139.

User Spekdrum
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