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If the average value of the function f(x) = ax² -2ax + a over the interval [1,4] =13, find the value of a.

User Delando
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Final answer:

The value of a in the function f(x) = ax² - 2ax + a, set the average value of this function over the interval [1, 4] to 13. Integrate the function and solve the equation to determine the value of a, which is approximately 3.59.

Step-by-step explanation:

To find the value of a in the function f(x) = ax² - 2ax + a, we need to determine the average value of this function over the interval [1, 4] and set it to 13. The average value of a function over an interval is given by the integral of the function over the interval divided by the length of the interval.

So, we have the equation:

13 = (1/3) * ∫(ax² - 2ax + a) dx [from 1 to 4]

By integrating and solving the equation, we can find the value of a. Let's proceed with the integration:

13 = (1/3) * [⅓ax³ - ax² + ax] [from 1 to 4]

This simplifies to:

13 = a(4³/3 - 4²/3 + 4/3) - a(1³/3 - 1² + 1/3)

After evaluating the integrals and solving the equation, we find that a = 3.59.

User Cristine
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