173k views
0 votes
On a coordinate plane, a line goes through (negative 5, negative 3), (negative 1, negative 2), and (3, negative 1). What would the y-intercept be???

User Marketta
by
8.0k points

1 Answer

5 votes

Final answer:

To find the y-intercept of a line, substitute the x and y values of a given point into the equation y = mx + b and solve for b.

Step-by-step explanation:

The y-intercept of a line can be found using the equation y = mx + b, where m represents the slope and b represents the y-intercept. To find the y-intercept, we need to determine the value of b. We can use one of the given points on the line and substitute the x and y values into the equation to solve for b.

Let's use the point (-5, -3). Substituting -5 for x and -3 for y in the equation y = mx + b, we can solve for b:

-3 = m(-5) + b

Using another given point as well, we can calculate the slope (m) of the line by using the formula m = (y2 - y1) / (x2 - x1). Once we have the slope, we can substitute it back into the equation to solve for b and determine the y-intercept.

User Ania
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories