Final answer:
Cyteria can prepare 12 plates with an equal number of crackers and pieces of cheese on each, based on the greatest common divisor (GCD) of the numbers of crackers (48) and pieces of cheese (36).
Step-by-step explanation:
The question asks how many plates Cyteria will have if she wants the same amount of crackers and pieces of cheese on each plate, and she has 48 crackers and 36 pieces of cheese.
To find the highest number of plates she can prepare with an equal amount of crackers and cheese on each, we need to find the greatest common divisor (GCD) of the numbers of crackers and pieces of cheese. The GCD of 48 and 36 is 12.
Therefore, Cyteria can prepare 12 plates, with 4 crackers (48/12) and 3 pieces of cheese (36/12) on each plate.