Final answer:
The equation of the line in point-slope form that goes through the point (-6,11) with a slope of 2/3 is y - 11 = (2/3)(x + 6).
Step-by-step explanation:
The equation of a line in point-slope form is expressed as y - y1 = m(x - x1), where (x1, y1) is a point on the line, and m is the slope of the line. To write the equation of the line that goes through the point (-6,11) with a slope of 2/3, we can directly plug these values into the point-slope form.
Here is the calculation for the equation:
y - 11 = (2/3)(x - (-6))
Simplifying further, we get:
y - 11 = (2/3)(x + 6)
The equation of the line is therefore y - 11 = (2/3)(x + 6).