Final answer:
The camera takes 11.33 seconds to hit the ground on Mars, with a velocity of -41.77 m/s. On Earth, with an acceleration due to gravity of -9.8 m/s^2, it would take 6.17 seconds.
Step-by-step explanation:
To find the time required for the camera to hit the ground on Mars, we can use the equation:
h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity, and t is the time. In this case, h = 239 m and g = -3.7 m/s^2. Plugging in these values, we get:
239 = (1/2)(-3.7)t^2
t^2 = (239 * 2) / -3.7 = -128.65
Since time cannot be negative, we take the positive square root of 128.65 to get t = 11.33 seconds (rounded to two decimal places).
To find the velocity with which the camera hits the ground on Mars, we can use the equation:
v = gt, where v is the velocity and g is the acceleration due to gravity. Plugging in g = -3.7 m/s^2 and t = 11.33 seconds, we get:
v = (-3.7)(11.33) = -41.77 m/s (rounded to two decimal places).
To find how long it would take for this camera to hit the ground on Earth, we need to know the acceleration due to gravity on Earth. Assuming g = -9.8 m/s^2, we can use the same equations as before. Using h = 239 m, g = -9.8 m/s^2, and solving for t, we get t = 6.17 seconds (rounded to two decimal places).